[3-2(x-10)]+[2(x-1)+2]=0

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Solution for [3-2(x-10)]+[2(x-1)+2]=0 equation: 


Simplifying
[3 + -2(x + -10)] + [2(x + -1) + 2] = 0

Reorder the terms:
[3 + -2(-10 + x)] + [2(x + -1) + 2] = 0
[3 + (-10 * -2 + x * -2)] + [2(x + -1) + 2] = 0
[3 + (20 + -2x)] + [2(x + -1) + 2] = 0

Combine like terms: 3 + 20 = 23
[23 + -2x] + [2(x + -1) + 2] = 0

Remove brackets around [23 + -2x]
23 + -2x + [2(x + -1) + 2] = 0

Reorder the terms:
23 + -2x + [2(-1 + x) + 2] = 0
23 + -2x + [(-1 * 2 + x * 2) + 2] = 0
23 + -2x + [(-2 + 2x) + 2] = 0

Reorder the terms:
23 + -2x + [-2 + 2 + 2x] = 0

Combine like terms: -2 + 2 = 0
23 + -2x + [0 + 2x] = 0
23 + -2x + [2x] = 0
23 + -2x + [2x] = 0

Combine like terms: -2x + [2x] = 0
23 + 0 = 0
23 = 0

Solving
23 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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